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0=420x-x^2
We move all terms to the left:
0-(420x-x^2)=0
We add all the numbers together, and all the variables
-(420x-x^2)=0
We get rid of parentheses
x^2-420x=0
a = 1; b = -420; c = 0;
Δ = b2-4ac
Δ = -4202-4·1·0
Δ = 176400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{176400}=420$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-420)-420}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-420)+420}{2*1}=\frac{840}{2} =420 $
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